Convert each mixed number to an improper fraction: 7 \(\frac{1}{12}\) = 7 + \(\frac{1}{12}\) = \(\frac{84}{12} + \frac{1}{12}\) = \(\frac{85}{12}\) 4 \(\frac{3}{4}\) = 4 + \(\frac{3}{4}\) = \(\frac{16}{4}\) + \(\frac{3}{4}\) = \(\frac{19}{4}\) 2 \(\frac{1}{2}\) = 2 + \(\frac{1}{2}\) = \(\frac{4}{2}\) + \(\frac{1}{2}\) = \(\frac{5}{2}\) Now calculate: \(\frac{85}{12} − \frac{19}{4} + \frac{5}{2}\) Common denominator = 12 \(\frac{85}{12}\) − (\(\frac{19}{4}\) \(\times\) \(\frac{3}{3}\)) + (\(\frac{5}{2}\) \(\times\) \(\frac{6}{6}\)) = \(\frac{85}{12}\) − \(\frac{57}{12}\) + \(\frac{30}{12}\) = (\(\frac{85 − 57 + 30)}{12}\) = \(\frac{(58)}{12}\) = \(\frac{29}{6}\) = 4 \(\frac{5}{6}\).