Evaluate \(\int_1 ^2(6x^2-2x)dx\)
A
16
B
13
C
12
D
11
Verified Correct Answer: D.
Step-by-Step Mathematical Solution
\(\int_1 ^2(6x^2-2x)\)dx = \(\frac{6x^3}{3}-\frac{2x^2}{2}]_1 ^2\)
= \(2x^3 - x^2)_1^2\)
= [2(2)3 - (2)2] – [2(1)3 - (1)2]
= [16-4] – [2-1]
= 12 – 1
= 11
Source: Myschool Past Questions Archive (Record #9291)