If \(4\sin^2 x - 3 = 0\), find the value of x, when 0^\circ \(\leq\) x \(\leq\) 90^\circ
A
90°
B
45°
C
60°
D
30°
Verified Correct Answer: C.
Step-by-Step Mathematical Solution
\(4\sin^2 x - 3 = 0\)
\(4 \sin^2 x = 3 \implies \sin^2 x = \frac{3}{4}\)
\(\sin x = \frac{\sqrt{3}}{2}\)
\(\therefore x = \sin^{-1} (\frac{\sqrt{3}}{2})\)
x = 60^\circ
Source: Myschool Past Questions Archive (Record #54992)