(a) Area of curved surface of cylinder = \(2\pi r h\) = \(2 \times \frac{22}{7} \times 7 \times 10cm^{2} = 440 cm^{2}\) Area of the base of cylinder = \(\pi r^{2}\) = \(\frac{22}{7} \times 7 \times 7 = 154 cm^{2}\) Surface area of hemisphere = \(\frac{4\pi r^{2}}{2} = 2 \pi r^{2}\) = \(2 \times \frac{22}{7} \times 7 \times 7 = 308 cm^{2}\) \(\therefore\) Total surface area = 440 + 154 + 308 = 902cm\(^{2}\) (b) Volume of cylinder = \(\pi r^{2} h\) = \(\frac{22}{7} \times 7 \times 7 \times 10 = 1540 cm^{3}\) Volume of hemisphere = \(\frac{1}{2}(\frac{4\pi r^{3}}{3})\) = \(\frac{4 \times 22 \times 7 \times 7 \times 7}{2 \times 7 \times 3}\) = \(718.67 cm^{3}\) Total volume = 1540 + 718.67 = 2258.67 cm\(^{3}\).