\(\frac{1+\sqrt{2}}{1-\sqrt{2}} \times \frac{1+\sqrt{2}}{1+\sqrt{2}}\) = \(\frac{1+(1+\sqrt{2})+\sqrt{2}(1+\sqrt{2})}{1^2 - (\sqrt{2})^2}\) = \(\frac{(1+\sqrt{2}+\sqrt{2}+2)}{1-2}\) = \(\frac{3+2\sqrt{2}}{-1}\) = - 3 - 2\(\sqrt{2}\) ∴ X and Y = -3 and -2