(a) Area of minor sector = \(\frac{\theta}{360} \times \pi r^{2}\) = \(\frac{96}{360} \times \frac{22}{7} \times 5^{2}\) = \(20.95 cm^{2}\) Area of triangle formed from the sector = \(\frac{1}{2} r^{2} \sin \theta\) = \(\frac{1}{2} \times 5^{2} \times \sin 96\) = \(12.43 cm^{2}\) \(\therefore \text{The area of minor segment} = 20.95 - 12.43\) = \(8.52 cm^{2}\) (b) Area of minor sector = \(\frac{\theta}{360} \times \pi r^{2}\) = \(\frac{80}{360} \times \frac{22}{7} \times 7^{2}\) = \(34.22 cm^{2}\) Area of the square = \((14)^{2} = 196 cm^{2}\) Area of the circle = \(\pi r^{2} = \frac{22}{7} \times 7^{2} = 154 cm^{2}\) Area of the shaded portion in the square = \(196 - 154 = 42 cm^{2}\) Total area of the shaded portions = \(42 + 34.22\) = \(76.22 cm^{2} \approxeq 76.2 cm^{2}\)