(a) From the pyramid, construct \(\Delta BFG\) by drawing a line from B to F. \(|BF|^{2} = 4^{2} + 3^{2}\) \(|BF| = 25 \implies |BF| = 5m\) In calculating the height, \(h^{2} = 5^{2} - (\frac{5}{2})^{2}\) \(h^{2} = \frac{75}{4}\) \(h = \sqrt{75}{4}\) = \(4.33 m\) Volume of a pyramid = \(\frac{1}{3} \times 4 \times 3 \times 4.33\) = \(17.32 m^{3}\) Volume of a cuboid = \(l \times b \times h\) = \(3 \times 4 \times 2\) = \(24 m^{3}\) Total volume of the shape = \(17.32 + 24\) = \(41.32 m^{3}\) (b) \(5 - (x - 2) = d\) \((x + 2) - 5 = d\) \(\therefore (x + 2) - 5 = 5 - (x - 2)\) \(x - 3 = 7 - x\) \(2x = 10\) \(x = 5\)