The diagram shows the cross- section of a railway tunnel. If |AB| = 100m and the radius of the arc is 56m, calculate, correct to the nearest metre, the perimetre of the cross- section.
Verified Correct Answer: .
Step-by-Step Mathematical Solution
From \(\Delta\) BCD,
\(\sin \theta = \frac{50}{56}\)
\(\theta = \sin^{-1} (0.8929)\)
\( < BCD = 63.23^\circ\)
\(\therefore < ACB = 63.23^\circ \times 2 = 126.46^\circ\)
\(< ACB (reflex) = 360^\circ - 126.46^\circ\)
= \(233.54^\circ\)
Perimeter of the arc = \(\frac{233.54}{360} \times 2 \times \frac{22}{7} \times 56\)
= \(228.35 m\)
Perimeter of the railway tunnel = Perimeter of the arc + |AB|
= 228.35 m + 100 m
= 328.35 m.
Source: Myschool Past Questions Archive (Record #52970)