The solution of the quadratic inequality (x\(^2\) + x - 12) \ge 0 is
A
x ≥ -3 or x ≤ 4
B
x ≥ 3 or x ≥ -4
C
x ≤ 3 or x \(\leq\) -4
D
x ≥ 3 or x ≤ -4
Verified Correct Answer: D.
Step-by-Step Mathematical Solution
(x\(^2\) + x - 12) \ge 0
(x + 4)(x - 3) \ge 0
Either x + 4 \ge 0 implies x \ge - 4
Or x - 3 \ge 0 implies x \ge 3
∴ x \ge 3 or x \(\leq\) -4
Source: Myschool Past Questions Archive (Record #9228)