A box contains two red balls and four blue balls. A ball is drawn at random from the box and then replaced before a second ball is drawn. Find the probability of drawing two red balls.
A
\(\frac{2}{3}\)
B
\(\frac{1}{3}\)
C
\(\frac{1}{4}\)
D
\(\frac{1}{9}\)
Verified Correct Answer: D.
Step-by-Step Mathematical Solution
Total number of balls = 2 + 4 = 6
P(of picking a red ball) = \(\frac{2}{6}\) = \(\frac{1}{3}\)
P(of picking a blue ball) = \(\frac{4}{6}\) = \(\frac{2}{3}\)
With replacement,
P( picking two red balls) = \(\frac{1}{3}\) \times \(\frac{1}{3}\) = \(\frac{1}{9}\)
Source: Myschool Past Questions Archive (Record #47586)