Profit (P) = 10\(_x\) − \(_x\)2 Maximum profit can be achieved when the differential of profit with respect to number of bags(x) is 0 i.e. \(\frac{dp}{dx}\) = 0 \(\frac{dp}{dx}\) = 10 - 2x = 0 10 = 2x Then x = \(\frac{10}{2}\) = 5 Answer is C