In the diagram, \(\bar{PF}\), \(\bar{QT}\), \(\bar{RG}\) intersect at S and PG||RG. If < SPQ = 113º and < RSt = 22º, find < PSQ
Attached Figure / Diagram
A
22o
B
45o
C
67o
D
89o
Verified Correct Answer: B.
Step-by-Step Mathematical Solution
In In the diagram given, \(\alpha\) = 22º (vertically opp. angles), \(\alpha\) = \(\beta\) (alternate angles)
< PSQ + 113º + \(\beta\) = 180º (sum of angles of a \(\Delta\))
< PSQ + 113º + 22º = 180º
< PSQ = 180º - (113 + 22)º
45º
Source: Myschool Past Questions Archive (Record #46170)