\(\frac{1}{4}\)p + 3p = 10...(1) 2p - \(\frac{1}{3}\)q = 7...(2) Multiply equation (2) by 3 to clear fraction 3 x 2p - 3 x \(\frac{1}{3}\)q = 3 x 7 6p - q = 21 6p - 21 = q....(3) substituting 6p - 21 for q in (1) \(\frac{1}{4}\)p + 3(6p - 21) = 10...(4) Multiply equation (4) by 4 to clear fraction 4 x \(\frac{1}{4}\)p + 4 x 3(6p - 21) = 4 x 10 p + 12(6p - 21) = 40 p + 72p - 252 73p = 292 p = \(\frac{292}{73}\) = 4