tan x = \(\frac{2}{3}\)(given), is illustrated in a right-angled \(\Delta\) thus m2 = 22 + 32 = 4 + 9 = 13 m = \(\sqrt{13}\) Hence, 2sin x = 2 x \(\frac{2}{m}\) 2 x\(\frac{2}{\sqrt{13}}\) = \(\frac{4}{\sqrt{13}}\) = \(\frac{4}{\sqrt{13}} = \frac{\sqrt{13}}{\sqrt{13}}\) = \(\frac{4\sqrt{13}}{13}\)