Using V = \(\frac{3}{1} \pi r^2h\), so, 38\(\frac{1}{2} = \frac{1}{3} \times \frac{22}{7} \times r^2 \times 3\) \(\frac{77}{2} = \frac{22}{7} \times r^2\) r2 = \(\frac{77 \times 7}{2 \times 22}\) r2 = \(\frac{49}{4}\) Hence, r = \(\sqrt{\frac{49}{4}}\) = 3\(\frac{1}{2}\)