Evaluate \(\int\)(cos4x + sin3x)dx
A
sin4x - cos3x + k
B
sin4x + cos3x + k
C
\(\frac{1}{4}\)sin4x - \(\frac{1}{3}\)cos3x + k
D
\(\frac{1}{4}\)sin4x + \(\frac{1}{3}\)cos3x + k
Verified Correct Answer: C.
Step-by-Step Mathematical Solution
\(\int (\cos 4x + \sin 3x) \mathrm d x\)
= \(\frac{1}{4} \sin 4x - \frac{1}{3} \cos 3x + k\)
Source: Myschool Past Questions Archive (Record #44769)