T varies inversely as the square root of F when T = 7, F = 2\(\frac{1}{4}\). Find T when F = \(\frac{27}{9}\)
A
1.5
B
6.1
C
6.3
D
12.6
E
21
Verified Correct Answer: B.
Step-by-Step Mathematical Solution
T ∝ \(\frac{1}{\sqrt{F}}\)
T = \(\frac{K}{\sqrt{F}}\)
K = T x \(\sqrt{F}\)
K = 7 x \(\frac{3}{2}\) = 10.5
T = \(\frac{10.5}{\sqrt{F}}\)
T = T = \(\frac{10.5}{\sqrt{3}}\) ≈ 6.1
Source: Myschool Past Questions Archive (Record #42664)