In the diagram above, POQ is a diameter of the circle PQRS. If ∠PSR = 145^\circ, find x^\circ
Attached Figure / Diagram
A
55o
B
45o
C
35o
D
25o
Verified Correct Answer: A.
Step-by-Step Mathematical Solution
∠PSQ = 90^\circ (∠ in semi circle)
∠PSQ + ∠QSR = 145^\circ
90 + ∠QSR = 145
∠QSR = 145 - 90
∠QSR = 55^\circ
BUt x^\circ = ∠QSR (∠s in the same segment)
∴x^\circ = 55^\circ
Source: Myschool Past Questions Archive (Record #8867)