A bag Contains 2 red, 3 blue and 4 green identical balls. If two balls are picked at random one after the other without replacement, what is the probability that both are green?
A
\(\frac{1}{6}\)
B
\(\frac{1}{3}\)
C
\(\frac{16}{18}\)
D
\(\frac{3}{8}\)
E
\(\frac{4}{9}\)
Verified Correct Answer: A.
Step-by-Step Mathematical Solution
No expanded working has been attached for this question yet. The verified answer is Option A.
Source: Myschool Past Questions Archive (Record #42331)