Given the first term \( a = 1.2 \) and common difference \( d = 2 \), the first five terms of the AP are: \(a_1 = 1.2\) \(a_2 = 1.2 + 2 = 3.2\) \(a_3 = 1.2 + 4 = 5.2 \) \(a_4 = 1.2 + 6 = 7.2 \) \(a_5 = 1.2 + 8 = 9.2\) The sum of the first five terms is: \(\text{Sum} = 1.2 + 3.2 + 5.2 + 7.2 + 9.2 = 26\) The mean is calculated as: \(\text{Mean} = \frac{26}{5} = 5.2\) Thus, the mean of the first five terms is \(5.2\).