0^\circ ∠ \theta ∠ 90º, From the diagram above, the adjacent by Pythagoras theorem = 3 Cos \theta = \(\frac{\text{adj}}{\text{hyp}}\) = \(\frac{3}{5}\) Tan \theta = \(\frac{\text{opp}}{\text{adj}}\) = \(\frac{4}{3}\) cos \theta + tan \theta = \(\frac{3}{5}\) + \(\frac{4}{3}\) = \(\frac{29}{15}\)