\(t^2\) + kt + \(\frac{25}{4}\) The general form of quadratic expression = ax\(^2\) + bx + c comparing \(t^2\) + kt + \(\frac{25}{4}\) and the general form a = 1, b = k and c = \(\frac{25}{4}\) using: b\(^2\) = 4ac we can find the value of k. ( note: there is/are another way(s) to find the value of k) k\(^2\) = 4 x 1 x \(\frac{25}{4}\) k\(^2\) = 25 taking the square root of both sides k = 5