Convert the binary to base 10 and they convert back to base two 100112 + xxxxx2 + 111002 + 1012 = 10011112 (1 × 24 + 0 × 23 + 1 × 22 + 1 × 21 + 1 × 20) + xxxxx2 +(1 × 24 + 1 × 23 + 1 × 22 + 0 × 21 + 0 × 20) + (1 × 22 + 0 × 21 + 1 × 20) = (16 + 0 + 0 + 2 + 1) + xxxxx2 + (16 + 8 + 4 + 0 + 0 ) + (4 + 0 + 1) =(64 + 0 + 0 + 8 + 4 + 2 + 1) 19 + xxxxx2 + 33 = 79 xxxxx2 + 52 = 79 xxxxx2 = 79 − 52 xxxxx2 = 2710 \( \begin{array}{c|c} 2 & 27 \\ \hline 2 & 13 \text{ rem 1}\\ 2 & 6 \text{ rem 1}\\ 2 & 3 \text{ rem 0}\\ 2 & 1 \text{ rem 1}\\ & 0 \text{ rem 1}\\ \end{array}\uparrow \) 2710 = 110112 Therefore xxxxx2 = 2710 = 110112