\( [ 1 ÷ 64^{(x + 2)}]= [4^{(x − 3)} ÷ 16^x ] \) \( 64^{−(x + 2)} = [4^{(x − 3)}] ÷[16^x] \) breakdown 4,16,64 into a small index no \( 2^{−6(x + 2)} = 2^{2(x − 3)} ÷ 2^{4(x)} \) \( 2^{−6x− 12} = 2^{2x − 4x − 6} \) \( 2^{−6x −12} = 2^{−2x − 6} \) − 6x − 12 = − 2x − 6 Collect the like term −6x + 2x = −6 + 12 −4x =6 x = \( \frac{6}{4} \) x = \( \frac{−3}{2} \)