\(\frac{1}{2}\)x + 2y = 3......(i)(multiply by 2) \(\frac{3}{2}\)x - 2y = 1......(ii)(multiply by 2) x + 4y = 6......(iii) 3x - 4y = 2.....(iv) add (iii) and (iv) 4x = 8, x = \(\frac{8}{4}\) = 2 substitute x = 2 into equation (iii) x + 4y = 6 2 + 4y = 6 4y = 6 - 2 4y = 4 y = \(\frac{4}{4}\) = 1(x + y) 2 + 1 = 3