From the diagram above B\(^2\) = 10\(^2\) - 6\(^2\) = 64 B = \(\sqrt{64}\) = 8 cm( B represent half the second diagonal not given) So, the second diagonal not given = 8 + 8 = 16cm. But, Area of a rhombus = \(\frac{1}{2}\) x both diagonals that is, \(\frac{1}{2}\) x d\(_1\) x d\(_2\) Area of a rhombus = \(\frac{1}{2}\) x 12 x 16 = 6 x 16 = 96cm\(^2\)