x + y = 2y - x + 1 = 5 x + y = 2y - x + 1 x + x + y - 2y = 1 2x - y = 1....(i) 2y - x + 1 = 5 -x + 2y = 5 + 1 -x = 2y = 4 x - 2y = -4 .....(ii) solve simultaneously (i) x 2x - y = 1 (ii) x x - 2y = -4 2x - y = 1 =2x - 4y = -8 3y = 9 y = \(\frac{9}{3}\) y = 3 substitute y = 3 into equation (i) 2x - y = 1 2x - 3 = 1 2x = 1 + 3 2x = 4 x = \(\frac{4}{2}\) = 2