Let the no. be x and x + 1 x + (x + 1) = \(\frac{5}{6}\) of x(x + 1) 2x + 1 = \(\frac{5}{6}\) x(x + 1) 6(2x + 1) = 5x2 + 5x 12x + 6 = 5x2 + 5x 5x2 + 5x - 12x - 6 = 0 5x2 - 7x - 6 = 0 5x2 - 10x + 3x - 6 = 0 5x(x - 2) + 3(x - 2) = 0 (5x + 3)(x - 2) = 0 (5x + 3)(x - 2) = 0 (5x + 3) = 0 x - 2 = 0 for (5x + 3) = 0 5x = -3 x = \(\frac{-3}{5}\) (Imposible since x is a whole number) x - 2 = 0 x = 2 x = \(\frac{-3}{5}\)(Impossible since x is a whole number) x - 2 = 0 x = 2 The numbers are x = 2 x + 1 = 2 + 1 = 3