make w the subject of the relation \(\frac{a + bc}{wd + f}\) = g
A
\(\frac{a + bc - fg}{dg}\)
B
\(\frac{a - bc + fg}{dg}\)
C
\(\frac{a + bc - f}{dg}\)
D
\(\frac{a + bc - dg}{dg}\)
Verified Correct Answer: A.
Step-by-Step Mathematical Solution
\(\frac{a + bc}{wd + f}\) = g(cross multiply)
a = bc + wdg + fg
wdg = a + bc - fg
w = \(\frac{a + bc - fg}{dg}\)
Source: Myschool Past Questions Archive (Record #36289)