Find the matrix T if ST = I where S = \(\begin{pmatrix} -1 & 1 \\ 1 & -2 \end{pmatrix}\)
A
\(\begin{pmatrix} -2 & -1 \\ -1 & -1 \end{pmatrix}\)
B
\(\begin{pmatrix} -2 & -1 \\ -1 & 1 \end{pmatrix}\)
C
\(\begin{pmatrix} -1 & -1 \\ 0 & -1 \end{pmatrix}\)
D
\(\begin{pmatrix} -1 & 1 \\ 0 & 1 \end{pmatrix}\)
Verified Correct Answer: A.
Step-by-Step Mathematical Solution
S = \(\begin{pmatrix} -1 & 1 \\ 1 & -2 \end{pmatrix}\)
and ST = I (Identity matrix).
This means T is the inverse of S
Find the determinant of S
\( \det(S)\) = (-1)(-2) - (1)(1) = 2 - 1 = 1
T = \(\frac{1}{\det(S)} \begin{pmatrix} -2 & -1 \\ -1 & -1 \end{pmatrix}\)
Since det = 1,
T = \(\begin{pmatrix} -2 & -1 \\ -1 & -1 \end{pmatrix}\)
T = \(\begin{pmatrix} -2 & -1 \\ -1 & -1 \end{pmatrix}\)
Source: Myschool Past Questions Archive (Record #11)