In the diagram, PR is a diameter of the circle centre O. RS is a tangent at R and QPR = 58o. Find < QRS
Attached Figure / Diagram
A
112o
B
116o
C
122o
D
148o
Verified Correct Answer: C.
Step-by-Step Mathematical Solution
PRQ = 90 - 58 = 32o(angle in a semi-circle)
Since PRS = 90o(radius angular to tangent)
QRS = 90 + 32
= 122o
Source: Myschool Past Questions Archive (Record #36205)