If p = [\(\frac{Q(R - T)}{15}\)]\(^ \frac{1}{3}\), make T the subject of the relation
A
T = R + \(\frac{P^3}{15Q}\)
B
T = R - \(\frac{15P^3}{Q}\)
C
T = R + \(\frac{P^3}{15Q}\)
D
T = 15R - \(\frac{Q}{P^3}\)
Verified Correct Answer: B.
Step-by-Step Mathematical Solution
Cubic both sides; P3 = \(\frac{Q(R - T)}{15}\)
(cross multiplication) Q(R - T) = 15P3
(divide both sides by Q); R - T = 15\(\frac{1}{Q}\)
(subtract r from both sides) - T = \(\frac{15P^3}{Q - R}\)
T = R - \(\frac{15P^3}{Q}\)
Source: Myschool Past Questions Archive (Record #36189)