Using cosine formula (t\(\sqrt{3}\))2 = t2 + t2 - 2t2 cos\(\theta\) 3t2 = 2t2 - 2t2 cos\(\theta\) = 2t2(1 - cos\(\theta\)) 1 - cos\(\theta\) = \(\frac{3t^2}{2t^2}\) = \(\frac{3}{2}\) cos = 1 - \(\frac{3}{2} = -\frac{1}{2}\) \(\theta\) = cos-1(-\(\frac{1}{2}\)) = 120o and 240o N.B 0 \(\geq\) \(\theta\) 360