In the figure, STQ = SRP, PT = TQ = 6cm and QS = 5cm. Find SR
Attached Figure / Diagram
A
\(\frac{47}{5}\)
B
5
C
\(\frac{32}{5}\)
D
\(\frac{22}{5}\)
Verified Correct Answer: A.
Step-by-Step Mathematical Solution
From similar triangle, \(\frac{QS}{QP} = \frac{TQ}{QR} = \frac{5}{12} = \frac{6}{QR}\)
QT = \(\frac{6 \times 12}{5} = \frac{72}{5} = SR = QR - QS\)
= \(\frac{72}{5} - 5 = \frac{72 - 25}{5}\)
= \(\frac{47}{5}\)
Source: Myschool Past Questions Archive (Record #32876)