In the figure, \(\bigtriangleup\)PQT is isosceles. PQ = QT, SRQ = 35o, TPQ = 20o and PQR is a straight line.Calculate TSR
Attached Figure / Diagram
A
20o
B
55o
C
75o
D
140o
Verified Correct Answer: C.
Step-by-Step Mathematical Solution
Given \(\bigtriangleup\) isosceles PQ = QT, SRQ = 35o
TPQ = 20o
PQR = is a straight line
Since PQ = QT, angle P = angle T = 20o
Angle PQR = 180o - (20 + 20) = 140o
TQR = 180o - 140o = 40o < on a straight line
QSR = 180o - (40 + 35)o = 105o
TSR = 180o - 105o
= 75o
Source: Myschool Past Questions Archive (Record #32838)