In the figure POQ is the diameter of the circle PQR. If PSR = 145o, find xo
Attached Figure / Diagram
A
25o
B
35o
C
45o
D
125o
E
55o
Verified Correct Answer: E.
Step-by-Step Mathematical Solution
< PRQ = \(\frac{1}{2}\) < POQ = 90o
< PSR + < PQR = 180o
< PQR = 180o - 145o = 35o
\(\bigtriangleup\)PQR is a right angled triangle
x = 90 - < PQR
= 90o - 35o
= 55o
Source: Myschool Past Questions Archive (Record #32806)