In the given figure, QRST is a rectangle with PT parallel to QM and ∠TPQ = 60^\circ. Since PT ∥ QM, and PQ is a transversal, the corresponding angle ∠PQM = 60^\circ, so the remaining angle ∠MQR = 90^\circ − 60^\circ = 30^\circ. Therefore, ∠MUR (the angle formed by the line from M through U to R) is supplementary to this 30^\circ angle, making it 180^\circ − 30^\circ = 150^\circ