Given that \(\sqrt[3]{{4}}\)\(^{2x}\) = 16, find the value of x
A
4
B
6
C
3
D
2
Verified Correct Answer: C.
Step-by-Step Mathematical Solution
3\sqrt42x = 16
this implies that (3\sqrt42x)3 = (16)3
42x = 42*3
42x = 46
∴ 2x = 6
x = 3
Source: Myschool Past Questions Archive (Record #8211)