Given the equation \[x^3 - 12x - 16 = 0\] with \( x = -2 \) as a solution, we can factor it as follows: Divide by \( x + 2 \) gives: \[x^3 - 12x - 16 = (x + 2)(x^2 - 2x - 8)\] Finding Roots of \( x^2 - 2x - 8 = 0 \) Using the quadratic formula: \[x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} = \frac{2 \pm \sqrt{36}}{2}\] This gives:\[x = 4 \quad \text{and} \quad x = -2 \text{ (with multiplicity 2)}\]