Solve the system of equation 2\(^{x + y}\) = 32, \(3^{3y - x}\) = 27
A
(3, 2)
B
(-3, 2)
C
(3, -2)
D
(-3, -2)
E
(2, 2)
Verified Correct Answer: A.
Step-by-Step Mathematical Solution
\(2^{x + y} = 32, 3^{3y - x}\) = 27
\(2^{x + y} = 2^5\)
\(3^{3y - x} = 3^3\)
equating powers, we have
x + y = 5 ------------1
3y - x = 3 ------------2
solving simultaneously(any method)
x = 3 and y = 2
Source: Myschool Past Questions Archive (Record #32632)