\(\frac{3e + f}{3f - e}\) = \(\frac{2}{5}\) = 3e + f = 2 x 1 \(\frac{-e + 3f}{3e - f}\) = \(\frac{5 \times 3}{2}\) = \(\frac{3e + 9f = 15}{10f = 17}\) f = \(\frac{17}{10}\) Sub. for equ. (1) 3e + \(\frac{17}{10}\) = 2 3e = 2 - \(\frac{17}{10}\) \(\frac{3}{10}\) e = \(\frac{3}{10}\) x \(\frac{1}{3}\) = \(\frac{1}{10}\) = e + 3f = \(\frac{1}{10}\) + \(\frac{3 \times}{10}\) = \(\frac{52}{10}\) f - 3e = \(\frac{17}{10}\) - 3 x \(\frac{1}{10}\) = \(\frac{14}{10}\) = \(\frac{52}{10}\) x \(\frac{10}{14}\) = \(\frac{26}{7}\)