Length of arc = \(\frac{\theta}{360}\) x 2\(\pi\)r = 6 \(\theta\) x 2\(\pi\)r = 360 x 6 \(\theta\) = \(\frac{360 \times 6}{2\pi r}\) Area of the sector = \(\frac{\theta}{360}\) x \(\pi\)r2 \(\frac{360 \times 6}{2\pi r}\) x \(\frac{1}{360}\) x \(\pi\)r2 = r = 3 x 7 = 21cm2