A bag contains 4 white balls and 6 red balls. Two balls are taken from the bag without replacement. What is the probability that they are both red?
A
\(\frac{2}{3}\)
B
\(\frac{2}{15}\)
C
\(\frac{1}{2}\)
D
\(\frac{1}{3}\)
Verified Correct Answer: D.
Step-by-Step Mathematical Solution
P(R1) = \(\frac{6}{10}\)
= \(\frac{2}{3}\)
P(R1 n R11) = P(both red)
\(\frac{3}{5}\) x \(\frac{5}{9}\)
= \(\frac{1}{3}\)
Source: Myschool Past Questions Archive (Record #32278)