In the diagram above, PQ = 4 cm and TS = 6 cm. If the area of parallelogram PQTU is 32 cm\(^2\), find the area of the trapezium PQRU
Attached Figure / Diagram
A
60 cm2
B
72 cm2
C
48 cm2
D
24 cm2
Verified Correct Answer: B.
Step-by-Step Mathematical Solution
Area of parallelogram PQTU = base * height
32 = 4 * h
w = 32/4
w = 8
∴ = Area of Trapezium PQRU = (1/2)(4 + 14) *8
= 1/2 * (18 * 8)
= 72 cm\(^2\)
Source: Myschool Past Questions Archive (Record #7974)