If P = \(\frac{\frac{2}{3}({1 - r^2})}{n^2}\), find n when r = \(\sqrt{\frac{1}{3}}\) and p = 1 p = \(\frac{\frac{2}{3}({1 - r^2})}{n^2}\) when r = \(\sqrt{\frac{1}{3}}\) and p = 1 1 = \(\frac{\frac{2}{3}({1 - (\sqrt{\frac{1}{3}})^2})}{n^2}\) \(n^2\) = \(\frac{2}{3}(1 - \frac{1}{3}\)) \(n^2\) = \(\frac{2 \times 2}{3 \times 3}\) = \(\frac{4}{9}\) n = \(\sqrt{\frac{4}{9}}\) = \(\frac{2}{3}\)