Find the mean of the distribution above
value
0
1
2
3
4
Frequency
1
2
2
1
9
A
1
B
2
C
3
D
4
Verified Correct Answer: C.
Step-by-Step Mathematical Solution
Mean = \(\frac{(0 \times 1) + (1 \times 2) + (2 \times 2) + (3 \times 1) + (4 \times 9)}{1 + 2 + 2 + 1 + 9}\)
= \(\frac{(0 + 2 + 4 + 3 + 36)}{15}\)
= \(\frac{45}{15}\) =3
Source: Myschool Past Questions Archive (Record #7842)