At what value of x is the function x\(^2\) + x + 1 minimum?
A
-1
B
\(-\frac{1}{2}\)
C
\(\frac{1}{2}\)
D
1
Verified Correct Answer: B.
Step-by-Step Mathematical Solution
x\(^2\) + x + 1
\(\frac{dy}{dx}\) = 2x + 1
At the turning point, \(\frac{dy}{dx}\) = 0
2x + 1 = 0
x = -\(\frac{1}{2}\)
Source: Myschool Past Questions Archive (Record #31474)