x + \(\frac{1}{x}\) = 4, find x2 + \(\frac{1}{x^2}\) = (x + \(\frac{1}{x}\))2 = x2 + \(\frac{1}{x^2}\) + 2 x2 + \(\frac{1}{x^2}\) = ( x + \(\frac{1}{x^2}\))2 - 2 = (4)2 - 2 = 16 - 2 = 14