Fifty boxes each of 50 bolts, were inspected for the number which were defective. The following was the result
No of defective per box
4
5
6
7
8
9
No. of boxes
2
7
17
10
8
6
The mean and the median of the distribution are, respectively
A
6.7, 6
B
7.6, 5
C
5.7, 87
D
34, 6
Verified Correct Answer: A.
Step-by-Step Mathematical Solution
No of defective(x)
No of boxes (f)
\(fx\)
4
2
8
5
7
35
6
17
102
7
10
70
8
8
64
9
6
54
\(\sum\)
50
333
\(Mean = \frac{\sum fx}{\sum f}\)
= \(\frac{333}{50} = 6.66 \approxeq 6.7\)
The median is the average of the 25th and 26th position = 6.
Source: Myschool Past Questions Archive (Record #31426)