From a point Z, 60 m north of X, a man walks 60√3m eastwards to another point Y. Find the bearing of Y from X.
A
0.30o
B
045o
C
060o
D
090o
Verified Correct Answer: C.
Step-by-Step Mathematical Solution
tan \(\theta\) = \(\frac{60\sqrt{3}}{60}\) = \(\sqrt{3}\)
\(\theta\) = tan \(\frac{1}{3}\) = 60o
Bearing of y from x = 060o
Source: Myschool Past Questions Archive (Record #31423)